Primary exercises
- Manually created factor.
In a study participants were asked whether their sport activity is none, oncePerWeek, severalPerWeek or daily.
Build a proper factor for the responses below and store it in a variable w.
Print the factor.
Write the code to count the numbers of occurrences of each level and print the counts.
severalPerWeek, none, none, oncePerWeek, oncePerWeek, oncePerWeek, oncePerWeek, ?, none, none
v <- c( "severalPerWeek", "none", "none", "oncePerWeek", "oncePerWeek", "oncePerWeek", "oncePerWeek", NA, "none", "none" )
w <- factor( v, levels = c( "none", "oncePerWeek", "severalPerWeek", "daily" ) )
w
[1] severalPerWeek none none oncePerWeek oncePerWeek
[6] oncePerWeek oncePerWeek <NA> none none
Levels: none oncePerWeek severalPerWeek daily
fct_count( w )
# A tibble: 5 × 2
f n
<fct> <int>
1 none 4
2 oncePerWeek 4
3 severalPerWeek 1
4 daily 0
5 <NA> 1
- A factor with a random content.
Read help about the function sample.
Then study and try the following lines of code to understand the results.
Next, understand why an error is generated and use replace argument to generate a vector with 100 samples.
Store this vector in a variable v and build a factor w from it.
Finally, count the numbers of occurrences of each level in w.
Ensure, that levels are in order provided in the variable lvs.
lvs <- c( "none", "oncePerWeek", "severalPerWeek", "daily" )
sample( lvs, 3 )
[1] "oncePerWeek" "daily" "none"
sample( lvs, 3 )
[1] "severalPerWeek" "none" "oncePerWeek"
sample( lvs, 3 )
[1] "none" "severalPerWeek" "daily"
sample( lvs, 100 )
Error in sample.int(length(x), size, replace, prob): cannot take a sample larger than the population when 'replace = FALSE'
v <- sample( lvs, 100, replace = TRUE )
w <- factor( v, levels = lvs )
w
[1] none none none severalPerWeek none
[6] oncePerWeek none daily oncePerWeek daily
[11] daily none severalPerWeek daily daily
[16] severalPerWeek none daily oncePerWeek none
[21] oncePerWeek oncePerWeek none daily none
[26] oncePerWeek daily none severalPerWeek oncePerWeek
[31] severalPerWeek severalPerWeek none severalPerWeek none
[36] severalPerWeek severalPerWeek oncePerWeek none daily
[41] daily oncePerWeek oncePerWeek severalPerWeek none
[46] oncePerWeek severalPerWeek oncePerWeek daily none
[51] oncePerWeek none none daily none
[56] none oncePerWeek severalPerWeek oncePerWeek daily
[61] none oncePerWeek oncePerWeek daily oncePerWeek
[66] oncePerWeek oncePerWeek daily severalPerWeek severalPerWeek
[71] severalPerWeek severalPerWeek severalPerWeek severalPerWeek oncePerWeek
[76] severalPerWeek daily none none oncePerWeek
[81] daily oncePerWeek none none none
[86] severalPerWeek oncePerWeek severalPerWeek none none
[91] none daily none severalPerWeek oncePerWeek
[96] oncePerWeek severalPerWeek severalPerWeek daily oncePerWeek
Levels: none oncePerWeek severalPerWeek daily
fct_count( w )
# A tibble: 4 × 2
f n
<fct> <int>
1 none 30
2 oncePerWeek 27
3 severalPerWeek 24
4 daily 19
- Reordering factor levels.
When a factor is shown on an axis of a plot, the order is given by its levels.
The factor w from the previous exercise will be then shown in this order: none, oncePerWeek, severalPerWeek, daily.
But for a picture in a manuscript the following order might be needed: daily, severalPerWeek, oncePerWeek, none.
Apply to w one of the fct_ functions from the tidyverse library to produce a factor w2 with the requested order.
Show the levels of w2.
Again show the number of elements of each level in w2 and compare it with the table of the previous exercise.
w2 <- fct_relevel( w, c( "daily", "severalPerWeek", "oncePerWeek", "none" ) )
levels( w2 )
[1] "daily" "severalPerWeek" "oncePerWeek" "none"
fct_count( w2 )
# A tibble: 4 × 2
f n
<fct> <int>
1 daily 19
2 severalPerWeek 24
3 oncePerWeek 27
4 none 30